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What is the energy (in ev) of an x-ray photon that has a wavelength of 2. 4 nm ?

Sagot :

Reideenidn

Answer:

  • E=518 eV

Explanation:

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λ=2,4 nm = 2,4·10⁻⁹ m

c=3·10⁸ m/s

h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s

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E - ?

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[tex]\displaystyle \boldsymbol{E}=h\nu =h \frac{c}{\lambda} =4,14\cdot 10^{-15} \; eV\cdot s\cdot \; \frac{3\cdot 10^8\; m/s}{2,4\cdot 10^{-9}\; m} =517,5\; eV\approx \boldsymbol{518\; eV}[/tex]

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