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When a 20. 0-ohm resistor is connected across the terminals of a 12. 0-v battery, the terminal voltage of the battery falls 0. 30 v. what is the internal resistance of this battery

Sagot :

Answer:

.513 Ω

Explanation:

The current through the 20 Ω load can be found to be

  (12-.3) v / 20 Ω  = .585 A

This current also flows through the internal resistance and produces the .3 v drop across this resistor

V/I  = R

.3 v / .585 A = .513 Ω  internal resistance

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