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The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.
According to the question,
The standard form of the equation whose graph is the line through (1, -2) and (-5, 6). Now first to find slope of the equation using below formula,
Slope of the equation (m)= (change in y axis) / (change in x axis)
= (6- (-2))/(-5 - 1)
= 8/-6
=-(4/3)
Slope of the equation (m) = -4/3. whose graph is the line through (1, -2) and (-5, 6).Formula to find Standard form of the equation is y = mx + c.
-2 = -(4/3) 1 + c
c = -2 +(4/3)
c = -2/3
The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2. y = -(4/3)x -(2/3).
⇒ 3y = -4x -2.
Hence, the standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.
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