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The equation which can be used to find the length of EF is option A which is EF=[tex]\sqrt{24^{2} -12^{2} }[/tex].
Given the length of base of right angled triangle is 12 and the hypotenuse be 24.
We are to find the length of EF and tell which equation can be used to find the length of EF.
We know that pythagoras theorem applies in a right angled triangle.
Pythagoras theorem says that in a right angled triangle the square of the hypotenuse is equal to the sum of square of base and perpendicular.
[tex]H^{2} =B^{2} +P^{2}[/tex]
In this triangle we are only given base and hypotenuse and we have to find EF which is perpendicular.
[tex](DE)^{2} =(EF)^{2} +(DF)^{2}[/tex]
EF=[tex]\sqrt{DE^{2}-DF^{2} }[/tex]
=[tex]\sqrt{(24)^{2} -(12)^{2} }[/tex]--1
=[tex]\sqrt{576-144}[/tex]
=[tex]\sqrt{432}[/tex]
Hence the equation which can be used to find the length of Ef is option A which is EF=[tex]\sqrt{24^{2} -12^{2} }[/tex].
Question is incomplete as it should include the figure also.
Learn more about pythagoras theorem at https://brainly.com/question/343682
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