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When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 600 k is equal to 1. 4×10^5j/mol. Calculate the equilibrium constant at 600 k.

Sagot :

The standard free energy change ΔG° at 600 K is equal to  1. 4×[tex]10^5[/tex]J/mol then the equilibrium constant at 600K is 0 .

Calculation ,

ΔG° = - RT㏑Kp

Where ΔG° = standard free energy change =  1. 4×[tex]10^5[/tex]J/mol

R = universal gas constant  = 8.3 J / K mol

T = temperature = 600K

Kp  = equilibrium constant

Now putting the value of all data in equation (i) we get ,

1. 4×[tex]10^5[/tex]J/mol = - 8.3 J / K mol × 600K ㏑Kp

- 1. 4×[tex]10^5[/tex]J/mol /8.3 J / K mol × 600K  = ㏑Kp

㏑Kp = - 6972×[tex]10^5[/tex]

Kp = 0

To learn more about  standard free energy change please click here ,

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