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A bucket contains exactly 3 marbles, one red, one blue and one green. a person arbitrarily pulls out each marble one at a time. What is the probability that the last marble removed is non-red?

Sagot :

The probability that the last marble removed is non-red is 2/3.

According to the given question.

Total number of marbles in a bucket = 3

And, a person arbitary pulls out each marble one at a time.

So, there are 6 possible sequences of removing 3 marbles.

Let R be the red marble, B be the blue marble and G be the green marble.

The possible sequences or sample space for removing marbles are: {RBG, RGB, BGR, BRG, GRB and GBR}.

Let A denotes the event of removing the non-red marbles at the last.

The favorable cases for event A are: RBG, RGB, BRG and GRB.

As, we know that probability of any event is calculated as by taking the ratio of total number of favorable outcomes to the total number of outcomes.

Thereofre,

The probability that the last marble removed is non-red

= 4/6

= 2/3

The probability that the last marble removed is non-red is 2/3.

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