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Magnetic field strength of the field is 4.2 × [tex]10^{-4}[/tex] T
What is Magnetic Field ?
The region of space where magnetic force is experienced is known as magnetic field.
The force on a particle of charge q moving at speed v at an angle Ф to a uniform magnetic field of flux density B is given as
F = BqvsinФ
Given that a proton travels with a speed of 8. 34×10^5 m/s at an angle of 32. 3° with the direction of a magnetic field. the field exerts a force of 3. 00×10^−17 N on the proton. What is the strength of the field?
The parameters are;
- Force F = 3.0 × 10^−17 N
- Speed V = 8.34 × 10^5 m/s
- Angle Ф = 32. 3°
- Magnetic field strength B = ?
- Proton charge = 1.6 x [tex]10^{-19}[/tex] C
Substitute all the parameters into the formula
F = BqvsinФ
3.0 × [tex]10^{-17}[/tex] = ( 1.6 x [tex]10^{-19}[/tex] x 8.34 x [tex]10^{5}[/tex] x sin 32.3 ) B
3.0 × [tex]10^{-17}[/tex] = 7.13 × [tex]10^{-14}[/tex] B
Make B the subject of formula
B = 3.0 × [tex]10^{-17}[/tex] / 7.13 × [tex]10^{-14}[/tex]
B = 4.2 × [tex]10^{-4}[/tex] T
Therefore, Magnetic field strength of the field is 4.2 × [tex]10^{-4}[/tex] T
Learn more about Magnetic field strength here: https://brainly.com/question/27750890
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