Answered

IDNLearn.com makes it easy to find precise answers to your specific questions. Discover in-depth answers from knowledgeable professionals, providing you with the information you need.

24. 00 ml of a 0. 25 m naoh solution is titrated with 0. 10m hcl. What is the ph of the solution after 24. 00 ml of the hcl has been added?.

Sagot :

Tutorconsortium330idn

The pH of the solution is 12.88.

Calculation:

millimoles of NaOH = volume x Molarity

                                 = 24.00 mL x 0.25 M

                                 = 6.00 mmole

millimoles of HCl = 24.00 mL x 0.10 M

                            = 2.40 mmole

Total volume = 48.00 mL

                           

                            NaOH + HCl   →     NaCl + H2O

initial                       6.00      0               0         0

added                                 2.40

change                   -2.40  -2.40      +2.40  +2.40

equilibrium               3.60    0           2.40    2.40

The pH is determined by the excess of NaOH present.

[NaOH] = millimoles/volume

            = 3.60/48.00

            = 0.075 M

pOH = -log (OH⁻).

        = -log (0.075)

        = 1.12

Then

pH + pOH = pKw = 14.00.

pH = 14 - pOH

pH = 14 - 1.12

pH = 12.88

Learn more about calculation of pH here:

https://brainly.com/question/9408394

#SPJ4

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.