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The angle between the two extreme vectors of Sofia bats is 74.60 degrees.
In this question,
The angle between two vectors will be deferred by a single point, which is called as the shortest angle at which we have to turn around one of the vectors to the position of co-directional with another vector.
The extreme vectors of Sofia bats are [tex]\vec u = < -8, 12 >[/tex] and [tex]\vec v = < -8, 12 >[/tex]
The angle between the vectors is
[tex]\theta = cos^{-1} \frac{\vec u.\vec v}{||\vec u|| ||\vec v||}[/tex]
The dot product is calculated as
[tex]\vec u. \vec v = (-8)(13)+(12)(15)[/tex]
⇒ [tex]-104+180[/tex]
⇒ 76
The magnitude can be calculated as
[tex]||\vec u|| = \sqrt{(-8 )^{2} +(12)^{2} }[/tex]
⇒ [tex]\sqrt{64+144}[/tex]
⇒ [tex]\sqrt{208}[/tex]
[tex]||\vec v|| = \sqrt{(13 )^{2} +(15)^{2} }[/tex]
⇒ [tex]\sqrt{169+225}[/tex]
⇒ [tex]\sqrt{394}[/tex]
Thus the angle between the vectors is
[tex]\theta = cos^{-1} \frac{76}{(\sqrt{208} )(\sqrt{394} )}[/tex]
⇒ [tex]\theta = cos^{-1} \frac{76}{\sqrt{81952} }[/tex]
⇒ [tex]\theta = cos^{-1} \frac{76}{286.27 }[/tex]
⇒ [tex]\theta = cos^{-1} (0.2654)[/tex]
⇒ [tex]\theta=74.60[/tex]
Hence we can conclude that the angle between the two extreme vectors of Sofia bats is 74.60 degrees.
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