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When 6a of ac current at 114 v flows in the primary coil of an ideal transformer, how many amps at 29 v wul flow in the secondary?

Sagot :

The current that will flow in the secondary coil will be 23.5 Amperes

Power is the rate per unit time, at which electrical energy is transferred by an electrical circuit.

The SI unit of power is the watt and is given by Voltage * Current

Let's solve the question:

Given:

Voltage ( Primary ) = Vp = 114 V

Current ( Primary ) = Ip = 6 A

Voltage ( Secondary ) = Vs = 29 V

Current ( Secondary ) = Is = ?

In Ideal Transformer Primary Power = Secondary Power

Therefore, Vp * Ip = Vs * Is

                  114 * 6 = 29 * Is

                   684 = 29 Is

                   Is = 23.5 Amperes

To learn more about Transformer click below :

https://brainly.com/question/15200241

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