Expand your knowledge base with the help of IDNLearn.com's extensive answer archive. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.
Sagot :
A string with mass density equal to 0. 0025 kg/m is fixed at both ends and at a tension of 290 n. Resonant frequencies are found at 558 Hz and the next one at 744 Hz. The length of the wire will be L = 0.91 m
A resonant frequency of a string is its natural frequency of a standing wave that is produced in it. The standing waves in the string are called harmonics. A string of a fixed length can have many standing waves. The frequencies of these standing waves are called resonant frequencies.
frequency = 1 / 2L ([tex]\sqrt{\frac{T}{mu} }[/tex])
L = length of the spring
T = Tension
fundamental frequency = 744 - 558 = 186 Hz
186 = 1/2(L) ([tex]\sqrt{\frac{290}{0. 0025 } }[/tex])
L = 340 / (186 * 2)
L = 0.91 m
To learn more about resonant frequency here
https://brainly.com/question/13191113
#SPJ4
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.