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Sagot :
The molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex] M if a substance x has a solubility of 2. 4 × [tex]10^{-5}[/tex] mg/l, and a molar mass of 188 g/mol.
Calculation ,
The number of moles dissolve in one liter of solution is called molar solubility.
Given Solubility = 2.4 × [tex]10^{-5}[/tex] mg/L
Solubility = 2.4 × [tex]10^{-5}[/tex] × [tex]10^{-3}[/tex] g/L = 2.4 × [tex]10^{-8}[/tex] g/L
Molar mass = 188 g/mol
Molar Solubility = 2.4 × [tex]10^{-8}[/tex] g/L / 188 g/mol = 0.012 × [tex]10^{-8}[/tex] mol/L
Molar Solubility = 1.2 × [tex]10^{-10}[/tex] M
Therefore , the molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex] M
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