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Sagot :
standard form of the given equation are
-f(*) = (x + 2)(x - 6) = x² - 4x - 12
f(x) = (x - 4)(x + 3) = x² - x - 12
f(x) = (x - 12)(x + 1) = x² - 11x - 12
f(x) = (x -3)(x + 4) = x² + x - 12
What is quadratic function?
A polynomial function with one or more variables in which the second-degree term is the highest degree is known as a quadratic function, quadratic polynomial, polynomial of degree 2, or simply a quadratic, in algebra.
What is standard form of a quadratic function?
As long as an is not equal to zero, the quadratic function f(x) = a(x - h)2 + k is considered to be in standard form. The graph starts out in either an upward or a downward direction depending on the value of a. The point at the vertex of the symmetry is represented by the vertical line x = h. (h,k).
According to the given information:
The standard form list.
1 . (x + 2)(x - 6)
= x² - 6x + 2x - 12
= x² - 4x -12
2. (x - 4)(x + 3)
= x² + 3x - 4x - 12
= x² - x - 12
3. (x - 12)(x + 1)
= x² + 1x - 12x - 12
= x² - 11x - 12
4. (x -3)(x + 4)
= x² + 4x - 3x - 12
= x² + x - 12
So the equivalent standard form of the give values are :
-f(*) = (x + 2)(x - 6) = x² - 4x - 12
f(x) = (x - 4)(x + 3) = x² - x - 12
f(x) = (x - 12)(x + 1) = x² - 11x - 12
f(x) = (x -3)(x + 4) = x² + x - 12
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I understand that the question you are looking for is:
Match each quadratic function given in factored form
with its equivalent standard form listed on the left.
f(x) = (x + 2)(x – 6)
f(x) = (x – 4)(x+3)
f(x) = (x – 12)(x+1)
f(x) = (x – 3)(x +4)
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