Uncover valuable information and solutions with IDNLearn.com's extensive Q&A platform. Discover the reliable solutions you need with help from our comprehensive and accurate Q&A platform.
Sagot :
The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.
c = 3 * [tex]10^{8}[/tex] m/s
∈ = 8.85 * [tex]10^{- 12}[/tex] [tex]C^{2}[/tex] / N/ [tex]m^{2}[/tex]
E = 0. 060 v/m
I = P / 4π[tex]r^{2}[/tex]
Also , I = c ∈ [tex]E^{2}[/tex] /2
[tex]r^{2}[/tex] = P / 4π I equation 1
substituting the value of I in equation 1
[tex]r^{2}[/tex] = 2 P / 4π (c ∈ [tex]E^{2}[/tex] )
[tex]r^{2}[/tex] = 2 * 27 * [tex]10^{-3}[/tex] / 4 * 3.14 * 3 * [tex]10^{8}[/tex] * 8.85 * [tex]10^{- 12}[/tex] * [tex](0.06)^{2}[/tex]
r = 21.21 m
To learn more about Electromagnetic waves here
https://brainly.com/question/12392559
#SPJ4
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.
