IDNLearn.com: Where questions are met with accurate and insightful answers. Ask anything and get well-informed, reliable answers from our knowledgeable community members.
Sagot :
The work done by the force field f! (x, y) = x sin(y)i + yj on a particle that moves along the parabola y = x2 from (−1, 1) to (2, 4) will be 15/2 + 1/2 cos1 -1/2 cos4
Work done on a body is equal to the increase in the energy of the body, for work transfers energy to the body. If, however, the applied force is opposite to the motion of the object, the work is considered to be negative, implying that energy is taken from the object.
The units in which work is expressed are the same as those for energy, for example, in SI (International System of Units) and the metre-kilogram-second system, joule (newton-metre)
Equation of parabola : y = [tex]x^{2}[/tex]
dy = 2x dx
f(x , y) = x sin (y) i + y j
= [tex]\int\limits^2__{} \, -1[/tex] [tex]\ {x sin (x^{2} )} \, dx[/tex] + [tex]\int\limits^2__{} \, -1[/tex] 2x . [tex]x^{2}[/tex] dx
= [tex]\int\limits^2__{} \, -1[/tex] [tex]\ {x sin (x^{2} )} \, dx[/tex] + [tex]\int\limits^2__{} \, -1[/tex] 2 [tex]x^{3}[/tex] dx
= 1/2[tex]x^{4}[/tex] * ( - 1/2 cos [tex]x^{2}[/tex] ) + [tex]x^{4}[/tex] / 2
= 8 - 1/2 + (-1/2 cos 4 + 1/2 cos 1)
= 15/2 + 1/2 cos1 -1/2 cos4
To learn more about work done here
https://brainly.com/question/13662169
#SPJ4
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.
