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Calculate the molality of a sulfuric acid solution containing 24. 4 g of sulfuric acid in 198 g of water

Sagot :

CrystalQueenidn

Answer:

1.26 m

Explanation:

The molality equation looks like this:

Molality = moles solute / mass solvent (kg)

In this case, sulfuric acid is the solute and water is the solvent. To calculate the molality, you need to (1) convert grams solute to moles solute (via molar mass), then (2) convert grams solvent to kilograms solvent, and then (3) calculate the molality.

(Step 1)

Molar Mass (H₂SO₄): 2(1.008 g/mol) + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (H₂SO₄): 98.073 g/mol

24.4 grams H₂SO₄                1 mole
-----------------------------  x  ------------------------  =  0.249 moles H₂SO₄
                                         98.073 grams

(Step 2)

198 grams H₂O                 1 kg
-------------------------  x  ----------------------  =  0.198 kg H₂O
                                    1,000 grams

(Step 3)

Molality = moles solute / mass solvent

Molality = 0.249 moles H₂SO₄ / 0.198 kg H₂O

Molality = 1.26 m

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