Discover new perspectives and gain insights with IDNLearn.com's diverse answers. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.

The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with b?
a)a+1
b)a-1
C)a+2
d)a+3
e)a+4


Sagot :

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

What is the average of five consecutive integers ending with b?

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

https://brainly.com/question/24369824

#SPJ1

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.