Answered

Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Get accurate and timely answers to your queries from our extensive network of experienced professionals.

Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of water at 25°C is 23.76 torr. (Assume ideal behavior.)

Sagot :

Pstnonsonjokuidn

The vapor pressure is obtained as 23.47 torr.

What is the vapor pressure?

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

x2 = mole fraction of the  of the solute

Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:https://brainly.com/question/14718830

#SPJ1

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.