Answer:
2/7 = 29% (nearest percent)
Step-by-step explanation:
Calculate the totals and add them to the table:
[tex]\begin{array}{| c | c | c | c | c | c |}\cline{1-6} & \sf Freshman & \sf Sophmore & \sf Juniors & \sf Seniors & \sf Total \\\cline{1-6} \sf Male & 4 & 6 & 2 & 2 & 14\\\cline{1-6} \sf Female & 3 & 4 & 6 & 3 & 16\\\cline{1-6} \sf Total & 7 & 10 & 8 & 5 & 30\\\cline{1-6}\end{array}[/tex]
Probability Formula
[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]
Let P(A) = probability that the student is a freshman
Let P(B) = probability that the student is male
Use the given table to calculate the probability that the student is male:
[tex]\sf \implies P(B)=\dfrac{14}{30}[/tex]
And the probability that the student is a freshman and male:
[tex]\implies \sf P(A \cap B)=\dfrac{4}{30}[/tex]
To find the probability that the student owns a credit card given that the they are a freshman, use the conditional probability formula:
Conditional Probability Formula
The probability of A given B is:
[tex]\sf P(A|B)=\dfrac{P(A \cap B)}{P(B)}[/tex]
Substitute the found values into the formula:
[tex]\implies \sf P(Freshman|Male)=\dfrac{\dfrac{4}{30}}{\dfrac{14}{30}}=\dfrac{4}{14}=\dfrac{2}{7}=0.28571...=29\%[/tex]
Therefore, the probability that the student is a freshman given they are male is 29% (nearest percent).
Learn more about conditional probability here:
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