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What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)?
OA.
y=3x+4
OB. y=3x-14
OC. y=3x-4
OD. y=3x + 12

Sagot :

Eunice1234idn

Answer: [tex]\Large\boxed{A.~y=3x+4}[/tex]

Step-by-step explanation:

Given information

Slope = 3

Point = (-3, -5)

Given the format of the equation

Slope-intercept form: y = mx + b

  • m = Slope
  • b = y-intercept

Substitute values into the equation

y = (3)x + b

y = 3x + b

Substitute the given point into the equation to get the value of [ b ]

(-5) = 3(-3) + b

-5 = -9 + b

b = -5 + 9

b = 4

Therefore, the equation of the line is [tex]\Large\boxed{y=3x+4}[/tex]

Hope this helps!! :)

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