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in a given figure if o is the centre of circle and oabc is a parallelogram find the value of abc

Sagot :

From the given information, we get the value of ABC = 120°.

How to estimate the value of ABC?

Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.

Now, the radius of the circle exists

OA = OB = OC

Opposite sides of a parallelogram are equal

AB = OC and OA = BC

In ∆OAB,

OA = OB = AB and,

In ∆OCB,

OC = OB = BC

Therefore, ∆OAB and ∆OCB exist in equilateral triangles.

All angles of an equilateral triangle are equivalent to 60°.

Hence, ∠ABC = ∠OBA + ∠OBC

∠ABC = 60° + 60°

∠ABC = 120°

Therefore, the value of ∠ABC = 120°.

To learn more about parallelogram refer to:

https://brainly.com/question/24291122

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