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Sagot :
The mean of the given data exists 20.026 and standard deviation exists at 0.50293.
What is a standard deviation?
A standard deviation (or σ) exists as a measure of how dispersed the data exists about the mean. Low standard deviation means data exist clustered about the mean, and high standard deviation suggests data exist better extended out.
Mean
= (1/10) [19.52+19.61+19.62+20.3+19.74+19.88+19.9+19.8+20.97+20.92]
= 200.26/10
= 20.026
Mean exists 20.026.
[tex]S^2=1/10[(19.52-20.026)^2+(19.61-20.026)^2+(19.62-20.026)^2+(20.3-20.026)^2+(19.74-20.026)^2+(19.88-20.026)^2+(19.9-20.026)^2+(19.8-20.026)^2+(20.97-20.026)^2+(20.92-20.026)^2][/tex]
= (1/10) [2.52944]
= 0.252944
To estimate standard deviation,
[tex]S = \sqrt{0.252944}[/tex]
= 0.50293
Therefore, the standard deviation exists at 0.50293.
Therefore, the correct answer is option D. σ = 0.50
To learn more about standard deviation refer to:
https://brainly.com/question/475676
#SPJ9
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