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a ball bearing x is dropped vertically downwards,from the edge of a table and it takes 0.5seconds to hit the floor. Another bearing y leaves from the edge of the table horizontally with a velocity of 5m/s . Find:.
a)the time taken for bearing y to reach the table?
b)the horizontal distance traveled by y before hitting the floor
c)the height of the table top above the floor level
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Sagot :

Answer:

See below

Explanation:

A) bearing y reaches the FLOOR in the same amount of time   .5 seconds  since there is no initial vertical velocity component

B.  in .5 seconds y will travel     5 m/s * .5 s = 2.5 meters horizontally

C.  d = 1/2 a t^2

         = 1/2 (9.81)(.5^2) = 1.23 m table height

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