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If 24. 7 g of barium chloride reacts with excess sodium sulfate, how many grams of sodium chloride will be produced

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Tushargupta0691idn

6.9 g of sodium chloride will be produced.

Antoine Lavoisier discovered in 1789 that mass is neither created nor destroyed in chemical reactions, which led to the formulation of the Law of Conservation of Mass. That is to say, the mass of any one element at the start of a reaction will be equal to that element's mass at the conclusion of the reaction.

The total mass of the reactants and products are equal under the principle of conservation of mass.

                  BaCl₂ + Na₂SO₄ => BaSO₄ + 2NaCl

Molecular weight of BaCl₂ = 137 + 35.5 × 2

                                            = 208 g/mole

Molecular weight of NaCl = 22.99 + 35.45

                                           = 58.44 g/mole

208 g/mol BaCl₂ produces 58.44 g/mole NaCl.

1 g/mol BaCl₂ produces (58.44 / 208) g/mole NaCl.

24.7 g  BaCl₂ produces   (58.44 / 208) × 24.7 g NaCl

                                       = 6.9 g NaCl

Therefore, 6.9g of sodium chloride will be produced.

Learn more about conservation of mass here:

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