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(a) time taken for the car to accelerate from v to 2v = t = [tex]\frac{2V-V}{a}[/tex]
(b) velocity of the car moving at 2t seconds = ΔV = 2at
(a) we know that,
a=[tex]\frac{V_{F}-V_{0} }{t}[/tex]
where, [tex]V_{F}[/tex] is the final velocity
[tex]V_{0}[/tex] is the initial velocity
a = acceleration
t = time
Time taken to accelerate from V to 2V:
t = [tex]\frac{2V-V}{a}[/tex]
(b) We know that,
a=[tex]\frac{V_{F}-V_{0} }{t}[/tex]
where, [tex]V_{F}[/tex] is the final velocity
[tex]V_{0}[/tex] is the initial velocity
a = acceleration
t = time
how fast is the car moving at 2t seconds after starting,
we can represent [tex]V_{F}[/tex] - [tex]V_{0}[/tex] = ΔV
at time = t= 2t, it becomes
a=[tex]\frac{V_{F}-V_{0} }{t}[/tex] = a = ΔV/2t
t= ΔV/2a
ΔV = 2at
Rate of change of velocity with time, both in terms of speed and direction is known as acceleration.
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