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Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive? (–[infinity], –3) (–[infinity], 3) (–3, [infinity]) (3, [infinity])

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the interval in which g(x) is positive is [3, ∞].

On what interval is the function positive?

Here we have the function:

g(x) = ∛(x - 3)

The interval in which the function is positive is defined by:

g(x) > 0.

Then we have:

∛(x - 3) > 0.

We need to solve that inequality for x.

∛(x - 3) > 0

The cube root respects the sign of the argument, then:

x - 3 > 0

x > 3

Then the interval in which g(x) is positive is [3, ∞].

If you want to learn more about intervals:

https://brainly.com/question/1503051

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