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In hydraulic machine, how can you lift heavier load by using small magnitude of force?‍

Sagot :

Hello, yes it is possible to lift heavier load using small magnitude of force.

How? let's see.

Do you know on which principle does hydraulic machine work? Yes, it's Pascal's Principle. So in order to understand how hydraulic machine will lift heavier weight using small magnitude of force we will have to take a look at Pascal's law.

Pascal's law : It sates that in a closed container filled with fluid when pressure is applied to any point that intensity of pressure transfers in all direction equally.

Now look at diagram,

Consider the left piston as X and Right Piston as Y.

the area of piston X is small (A1) and applied force (F1) is also less and the resultant pressure is P.

[tex]P = \frac{F_1}{A_1}[/tex]

This same amount of pressure will be exerted at Piston Y having area (A2) and resultant output force (F2)

[tex]P = \frac{F_2}{A_2}[/tex]

So consider I have 5 N force and I have to lift a heavier rock weighing 50 N. take an example the area of Piston X is 1 m² & area of piston Y is 10 m²

So when I will apply 5 N force on piston X it will exert 50 N force on piston Y.

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