The vertex of the function is a minimum and the coordinate of the vertex of the function is (0.2, -2.4)
Part A: What are the x-intercepts of the graph of f(x)
The function is given as:
f(x) = 5x^2 + 2x - 3
Expand the function
f(x) = 5x^2 + 5x - 3x - 3
Factorize the function
f(x) = (5x - 3)(x + 1)
Set the function to 0
(5x - 3)(x + 1) = 0
Solve for x
x = 3/5 and x =-1
Hence, the x-intercept is 3/5 and -1
Is the vertex of the graph of f(x) going to be a maximum or a minimum?
The vertex of the function is a minimum.
This is so because the leading coefficient of the function is positive
What are the coordinates of the vertex?
Here, we have:
f(x) = 5x^2 + 2x - 3
Differentiate and set to 0
10x + 2 = 0
Solve for x
x = -0.2
Substitute x = -0.2 in f(x) = 5x^2 + 2x - 3
f(0.2) = 5(0.2)^2 + 2(0.2) - 3
Evaluate
f(0.2) = -2.4
Hence, the vertex of the function is (0.2, -2.4)
What are the steps you would use to graph f(x)?
To do this, we simply plot the x-intercept and the vertex.
And then connect the points
Read more about quadratic functions at:
https://brainly.com/question/23680118
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