Answered

IDNLearn.com: Your trusted source for finding accurate and reliable answers. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.

The length of a rectangular poster is 5 more inches than half its width. The area of the poster is 12 square inches. Solve for the dimensions (length and width) of the poster.

Sagot :

MrRoyalidn

The dimensions (length and width) of the poster are 6 inches and 2 inches

How to determine the dimensions (length and width) of the poster?

Represent the length with x and the width with y

From the question, we have the following parameters

x = 5 + 0.5y

Area, A = 12

The area of a rectangle is represented as:

A = xy

Substitute the known values in the above equation

(5 + 0.5y) * y = 12

Expand the bracket

5y + 0.5y^2 = 12

Multiply through by 2

10y + y^2 = 24

Rewrite as:

y^2 + 10y - 24 = 0

Expand

y^2 + 12y - 2y - 24 = 0

Factorize the expression

(y - 2)(y + 12) = 0

Solve for y

y = 2 or y = -12

The dimension cannot be negative.

So, we have

y = 2

Substitute y = 2 in x = 5 + 0.5y

x = 5 + 0.5 * 2

Evaluate

x = 6

Hence, the dimensions (length and width) of the poster are 6 inches and 2 inches

Read more about area at:

https://brainly.com/question/24487155

#SPJ1

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.