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The force that the spring exerts is 1.31 N.
[tex]E_{stored} =\frac{1}{2} kx^{2}[/tex]
F = kx
Where,
x = displacement in the spring
k = spring force constant
Given,
k = 8.75 n/m
x = 0.150 m
Force exerted by the spring, F = kx
putting the values,
F = 8.75 x 0.150
= 1.3125 N
Hence, the force that the spring exerts is 1.31 N.
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