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Rewrite 2x = 128 as a logarithmic equation.
Ologx128=2
O log2x = 128
O log₂128 = x
Olog128x = 2

Sagot :

Facundo3141592idn

The logarithmic equation is:

log₂128 = x

So the correct option is the third one

How to rewrite this as a logarithmic equation?

Here we have the expression.

2ˣ = 128

Now, if we apply the natural logarithm to both sides, we can get:

ln(2ˣ) = ln(128)

Because of the property of natural logarithms, we can write the left side as:

ln(2ˣ) = x*ln(2) = ln(128)

Now, if we isolate x, we get:

x = ln(128)/ln(2)

And remember that:

ln(k)/ln(n) = logₙ(k)

Then we can rewrite the logarithmic equation as:

x = log₂(128)

Which is the third option.

If you want to learn more about logarithmic equations, you can read:

https://brainly.com/question/236421

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