[tex]\lim _{x\to \infty }\left(\frac{tanx-sinx}{x^2}\right)[/tex]

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Phong2k1973idn Phong2k1973idn

05-08-2022
Mathematics

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[tex]\lim _{x\to \infty }\left(\frac{tanx-sinx}{x^2}\right)[/tex]

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LammettHashidn LammettHashidn · Answer 1 · 2022-08-05T04:51:50-04:00

LammettHashidn LammettHashidn

05-08-2022

The limit does not exist. There are infinitely many infinite discontinuities at [tex]x=n\pi[/tex], where [tex]n\in\Bbb N[/tex]. The function oscillates wildly between negative and positive infinity.

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