Princegyabeng22idn
Answered

Get the best answers to your questions with the help of IDNLearn.com's experts. Get prompt and accurate answers to your questions from our community of knowledgeable experts.

accelerates uniformly at 2.0 ms2 for 10.0s. Calculate its final velocity​

Sagot :

Nabinkriwaramidn

Answer:

The distance is

=

7

m

Explanation:

Apply the equation of motion

s

(

t

)

=

u

t

+

1

2

a

t

2

The initial velocity is

u

=

0

m

s

−

1

The acceleration is

a

=

2

m

s

−

2

Therefore, when

t

=

3

s

, we get

s

(

3

)

=

0

+

1

2

⋅

2

⋅

3

2

=

9

m

and when

t

=

4

s

s

(

4

)

=

0

+

1

2

⋅

2

⋅

4

2

=

16

m

Therefore,

The distance travelled in the fourth second is

d

=

s

(

4

)

−

s

(

3

)

=

16

−

9

=

7

m

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.