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Organizers of the town fair make a total of $706 from selling 164 hot dogs and 74 hamburgers at one of their concession stands. at their other concession stand, they make $884 by selling 256 hot dogs and 61 hamburgers. if the prices are the same at both concession stands, what is the price of a hot dog?

Sagot :

The price of a hot dog  is $2.5

How to solve a system of two equations?

First of all, we should obtain one variable in representations of another variable in one equation and substitute this variable in another equation. And solving that we bring two variables value. If you have two separate equations with identical two unknowns in each, you can solve for both unknowns. There are three common forms for solving: addition/subtraction, substitution, and graphing.

Here,

let's assume the price of hot dogs = x and the price of hamburgers = y

then, 164x + 74y = $706 --- ( 1 )

and 256x + 61y = $884 --- ( 2 )

Now, from eq - 1 we obtain x = ($706 - 74y) / 164

Substitute this x value in eq - 2,

256($706 - 74y)/164 + 61y = $884

=> $706*256 - 74y*256 + 61y*164 = $884 * 164

=> 180,736-8940y = 144,976

=> 180,736 - 144,976 = 8940y

=> 35,760/8940 = y

=> y = $4.

By substituting in eq - (1) we get x = $2.5

So, The price of a hot dog  is $2.5

To learn more about system of two equations refer to:

https://brainly.com/question/14502046

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