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please answer the question so i can make sure I got them right! thank you :)

Please Answer The Question So I Can Make Sure I Got Them Right Thank You class=

Sagot :

pH = pKa + log [conj.base]/[acid]

Let the concentration of the conjugate base = x

=> The concentration of the acid is also x (As the acid concentration is equivalent to that of the conjugate base)

for CH₃COOH=0.50 M and CH₃COO=0,25 M

pH = pKa + log [salt]/[acid]

pKa = -log Ka = -log 1.8x10-5 = 4.74

pH = 4.74 + log (0.50 M/1.0 M) = 4.74 + log 0.5 = 4.74 + (-0.3)

pH = 4.74 - 0.3

pH = 4.44

For0.20 M Na2CO3

pH=−log[H+]

    =−log (1.54×10−12)

   =11.8

for HNO₂

Kb = 2.17X10^-11 = x^2 / 0.148

x = [OH-] = 1.79X10^-6

pOH = 5.747

pH = 14.000 - pOH = 8.253

​

for HPO₄³⁻

= [HPO₄³⁻] [PO₄³⁻] [H +]/×10⁻³

=[PO₄³⁻]5.464×10⁻¹⁸

Learn more about conjugate base here=

https://brainly.com/question/12883745

#SPJ1

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