Minniemawidn
Answered

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Simplify the following, leaving your answers in positive index form.

(a) 3[tex]b^{3} [/tex] x 4[tex]b^{5} [/tex]

(b) 3[tex] x^{2} y^{3} [/tex] ÷ 9[tex] y^{5} [/tex]

Sagot :


a is 12(b^8)

b is (x^2)/(3(y^2))

Eu99liidn
[tex](a) 3b^3*4b^5=(3*4)b^{3+5}=12b^8 \\ \\ (b) \frac{3x^2y^3}{9y^5} = \frac{3x^2y^3}{3y^3*3y^2} ^{/3y^3}= \frac{x^2}{3y^2} [/tex]
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