Experience the power of community-driven knowledge on IDNLearn.com. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

A rectangles length is 7 inches greater than its width. If the perimeter of the rectangle is 110 inches, find its length and width.
I think it's w (w+7)=110


Sagot :

the equation for perimeter is P=2(l+w)
so, the equation is 110=2(l+w)
we know that l is 7 inches greater than w
so, l=w+7
now, substitute that for l
110=2(w+7+w)
110=2(2w+7)
110=4w+14
96=4w
w=24
ythat's wrong, perimiter is 2l+2w or 2(l+w) or just look below at my explanation

l=w+7

perimiter=2l+2w
perimiter=2(l+w)
subsitute
2(w+7+w)=permiter
2w+14+2w=4w+14=permiter

4w+14=110
subtract 14 from both sides
4w=96
divide both sides by 4
w=24

width=24
l=w+7
l=24+7
l=31


legnth=31
width=24
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.