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Where is the midpoint of (6,11) and (10,16)

Use the rules of negative numbers to calculate -5+-7--3

Sagot :

TSOidn
[tex](\frac{x_1 +x_2}{2},\frac{y_1 +y_2}{2})[/tex]

Is the formula for finding the midpoint
So 
6+10=16 /2 =8
11+16= 27 /2 = 13.5

So your answer is
(8, 13.5)
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