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There are 2 buildings, A & B. A has twice as many visitors as B. 2,950 visitors from B went to A. Now, A has 39,500 more visitors than B. How many visitors altogether?

Sagot :

Anthougoidn

Altogether, the number of visitors in the two buildings, A and B is 112,600 visitors.

How is the number computed?

If Building A's visitors are 39,500 more than visitors in B, then the visitors in B = 39,500 - 2,950, which is 36,550.

Initially, Building A's visitors were 73,100 (36,550 x 2) and then 2,950 came from Building B, making the total in Building A 76,050 (73,100 + 2,950).

Data and Calculations:

Let Building A's visitors = 2b

Let Building B's visitors = b

Building A's visitors = 2b + 2,950

b = 39,500 - 2,950

B's = 36,550

A's visitors = 36,550 + 39,500 = 76,050

Total visitors = 112,600 (76,050 + 36,550)

Check:

A's visitors = 76,050

B's visitors = 36,550

Difference = 39,500 (76,050 - 36,550)

Thus, altogether, there are 112,600 visitors (76,050 in Building A and 36,550 in Building B).

Learn more about mathematical operations at https://brainly.com/question/20628271

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