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First you have to multiply the numbers out of the paranthesis, with the numbers in it: [tex]-3(4v+1)-3(2v+3)\\ -3\cdot 4v-3\cdot 1-3\cdot 2v-3\cdot 3 [/tex] then solve : [tex]-12v-3-6v-9\\ -18v-12[/tex]
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