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in how many ways can i arrange 3 different math books and 5 different history books on my bookshelf, if i require there to be a math book on both ends?

Sagot :

by permutation there are 4320 ways.

We have   P(3,2)  =  6 ways to arrange the math books by permutation  

6! ways of arranging the 1 math book

5 history books in the middle....

so...6 x 6!  =   6 x 720  =  4320 ways

learn more about permutation here:

https://brainly.com/question/10525991

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