Find expert answers and community insights on IDNLearn.com. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.
Sagot :
the sum of the numbers are 794.
The numbers are 1, 64 and 729.
Let the required number be N.
Let N be a perfect square of A.
We have A^2=N. —(1)
Let N be a perfect cube of B.
We have B^3=N. —(2)
From (1) and (2) we get:
B=A^(2/3)
For B to e an integer, A must be the cube of some other integer (say C).
Therefore,
A=C^3
B=C^2
Now, starting with C = 1
A = 1
B = 1
N = 1
For C = 2
A = 8
B = 4
N = 64
For C = 3
A = 27
B = 9
N = 729.
therefore sum=794.
learn more about sum here:
https://brainly.com/question/2289438
#SPJ9
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.
