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find the mechanical energy of a block–spring system with a spring constant of 1.3 n/cm and an amplitude of 2.4 cm.

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The mechanical energy of a block–spring system with a spring constant of 1.3 n/cm and an amplitude of 2.4 cm is: 3.7×10^²J.

Mechanical energy

Using this formula

Mechanical Energy (M.E.) = ((1/2)mv²)

Where:

m = mass of object

v = velocity of object

Let plug in the formula

Mechanical Energy (M.E.) = (1/2) (1.3×10²N/m)  (0.024m)²

Mechanical Energy (M.E.) =  3.7×10^²J

Therefore the mechanical energy of a block–spring system with a spring constant of 1.3 n/cm and an amplitude of 2.4 cm is: 3.7×10^²J.

Learn more about Mechanical energy here:https://brainly.com/question/24443465

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