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The solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8
2 and 1 over 10 times negative seven times 5 over 12 can also be expressed as; 2¹/₁₀ * ⁽⁻⁷ * ⁵⁾/₁₂
Multiplying out the bracket gives;
²¹/₁₀ * -³⁵/₁₂
Dividing by common factors gives;
= ⁷/₂ * ⁻⁷/₄
= -49/8
= -6¹/₈
This can also be written as negative six and 1 over 8
Thus, we conclude that the solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8
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