Answered

Get comprehensive solutions to your problems with IDNLearn.com. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.

a railway truck of mass 8000 kg travels along a level track at a velocity of 2.5 m s–1 and collides with a stationary truck of mass 12 000 kg. the collision takes 4.0 s and the two trucks move together at the same velocity after the collision. what is the average force that acts on the 8000 kg truck during the collision?

Sagot :

The average force that acts on the 8000 kg truck during the collision is 12000kgm/s.

Impulse is the change in momentum of the body.

Mass, M = 8000kg

Time, t = 4s

Mass, m = 12000kg

Velocity, V = 2.5m/s

Let the Final velocity be v.

Using conservation of momentum to find out the final velocity of the truck,

MV = (M+m)v

8000×2.5 = (8000+12000)×v

v = 1m/s

Now the Initial momentum is MV = 8000×2.5 = 20000kgm/s

Final Momentum is Mv = 8000×1 = 8000kgm/s

Change in Momentum = 20000 - 8000

Change is Momentum = 12000kgm/s

Change is momentum is equal to the average force that acts on the truck from the Newton law of motion.

Hence, the average force that acts on the 8000 kg truck during the collision is 12000kgm/s.

Learn more about Impulse here, https://brainly.com/question/16980676

#SPJ4

We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.