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a toy train moves around a circular track, of radius 0.55 m, 10 complete times over 3 minutes. what is the train’s average speed?

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The toy train that moves around a circular track, of radius 0.55 m, 10 complete times over 3 minutes has a speed of: 0.1919 m/s

To solve this problem the formulas and the procedures we will use are:

v = (2*π * r * n)/ t

Where:

  • v = tangential velocity
  • π = mathematical constant
  • r = radius
  • n = number of laps
  • t = time

Information about the problem:

  • r = 0.55 m
  • n = 10
  • t = 3 min
  • π = 3.1416
  • v=?

By converting the time unit from (min)  to (s) we have:

t = 3 min * 60 s/1 min

t = 180 s

Applying the tangential velocity formula we get:

v = (2*π * r * n)/ t

v = (2* 3.1416 * 0.55 m * 10)/ 180 s

v = 0.1919 m/s

What is tangential velocity?

In physics is the length of arc traveled in each unit of time in uniform circular motion. It is expressed in units of distance per time (m/s), (km/h).

Learn more about tangential velocity at: brainly.com/question/19660334

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