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an ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. this sum is recorded as the outcome of a single trial of a random experiment. compute the probability of each of the following events. event : the sum is greater than 5. event : the sum is divisible by 2 or 3 (or both).

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Probability of sum greater than 5 event is reduces to 13/18 .

probability of getting number whose sum is divisible by 2 and 3 both is 6/36 which reduces to 1/6 .

The sample space of rolling two dice has 36 possible outcomes.  Remember that the "sample space" is a set which contains all possible outcomes.  

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

(1,4)(2,4)(3,4)(4,4)(5,4)(6,4)

(1,5)(2,5)(3,5)(4,5)(5,5)(6,5)

(1,6)(2,6)(3,6)(4,6)(5,6)(6,6)

The probability of the sum is greater than 5 event is 26/36 which reduces to 13/18 .

And the probability of getting number whose sum is divisible by 2 and 3 both is 6/36.

To learn more about probability visit brainly.com/question/11234923

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