Answered

Discover the best answers to your questions with the help of IDNLearn.com. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

two small charged objects repel each other with a force 2.53 when separated by a distance 0.11. if the charge on each object is reduced to 67.9% of its original value and the distance between them is reduced to 0.053 the force becomes

Sagot :

The force between the charges will be 10.9 N.

What is the electrostatic force?

The electrostatic attraction particles that make up the electrostatic force behave as both an attracting and a repulsive force. The force is inversely proportional to the square of the distance between them.

F ∝ 1 / r²

F = k / r²

Fr² = k

When two tiny charged objects are 0.11 of a distance apart, they repel one another with a force of 2.53. If the distance between the two particles is cut to 0.053 and the charge on each item is decreased to 67.9% of its initial amount. Then the force will be

F₁r₁² = F₂r₂²

2.53 × (0.11)² = F × (0.053)²

F = 10.9 N

More about the electrostatic force link is given below.

https://brainly.com/question/9774180

#SPJ4

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.