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Sagot :
The probability that the number of heads obtained from flipping the two fair coins is the same is 35/128.
Probability:
Probability means the fraction of favorable outcome and the total number of outcomes.
So it can be written as,
Probability = Favorable outcomes / Total outcomes
Given,
The coin a is flipped three times and coin b is flipped four times.
Here we need to find the probability that the number of heads obtained from flipping the two fair coins is the same.
We know that,
There are 4 ways that the same number of heads will be obtained;
0, 1, 2, or 3 heads.
The probability of both getting 0 heads is
[tex]$\left(\frac12\right)^3{3\choose0}\left(\frac12\right)^4{4\choose0}=\frac1{128}$[/tex]
Probability of getting 1 head,
[tex]$\left(\frac12\right)^3{3\choose1}\left(\frac12\right)^4{4\choose1}=\frac{12}{128}$[/tex]
Probability of getting 2 heads is,
[tex]$\left(\frac12\right)^3{3\choose2}\left(\frac12\right)^4{4\choose2}=\frac{18}{128}$[/tex]
And the probability of getting 3 heads is,
[tex]$\left(\frac12\right)^3{3\choose3}\left(\frac12\right)^4{4\choose3}=\frac{4}{128}$[/tex]
Therefore, the probability that the number of heads obtained from flipping the two fair coins is the same is,
=> (1/128) + (12/128) + (18/128) + (4/128)
=> 35/128.
To know more about probability here
https://brainly.com/question/14210034
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