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Sagot :
The cost of the Coca-Cola can will be $1 in the year 2000.
Given that the cost of a can of Coca-Cola can in 1960 = $0.10
The function which models the cost of a Coca-Cola by year 't' is
c(t) = [tex]0.10e^{0.0576t}[/tex].
Here, 't' denotes the number of years since 1960.
c(t) is an exponential function.
We have to find the year in which the cost of a can will be $1.
So substitute c(t) = 1, we get,
1 = [tex]0.10e^{0.0576t}[/tex]
⇒ [tex]10 = e^{0.0576t}[/tex]
We have, [tex]ln(e^x) = x[/tex] .
Taking logarithm on both sides, we get,
log(10) = 0.0576t
⇒ [tex]t=\frac{ln(10)}{0.0576}[/tex] = 39.97 ≈ 40 years .
Thus the cost of a can of Coca-Cola will be $1 in the year, 1960 + 40 = 2000.
The question was incomplete. Find the complete question at:
The cost of a can of Coca-Cola in 1960 , was $0.10. The function that models the cost of a Coca-Cola by year is C(t)=0.10e^(0.0576t) , where t is the number of years since 1960 . In what year is it expected that a can of Coca-Cola will cost $1.00 ?
Learn more about exponential functions at https://brainly.com/question/23049613
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